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Intersection of two channels

Once each channel has been fitted to a line, the intersection of any two channels C1 and C2 can be computed by finding the two points and belonging to C1 and C2 respectively such that the distance between them is the smallest possible. Let the equations of C1 and C2 be:

Since the shortest distance between a point and a line is that measured perpendicularly to the line, the shortest line segment between C1 and C2 is perpendicular to both of these lines. This can be expressed vectorially by:

 

where C is a constant. Furthermore, the fact that and gives the equations:

which can also be written:

  

The seven scalar unknowns that constitute , and C can be determined by using the three scalar equations given by the vectorial equation paral together with the four independent scalar equations given by the vectorial equations in1 and in2.



Patrice MUNGER
Mon Oct 23 15:09:17 EDT 1995